9x^2+36x=43

Solution for 9x^2+36x=43 equation:

9x^2+36x=43

We move all terms to the left:

9x^2+36x-(43)=0

a = 9; b = 36; c = -43;
Δ = b2-4ac
Δ = 362-4·9·(-43)
Δ = 2844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2844}=\sqrt{36*79}=\sqrt{36}*\sqrt{79}=6\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6\sqrt{79}}{2*9}=\frac{-36-6\sqrt{79}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6\sqrt{79}}{2*9}=\frac{-36+6\sqrt{79}}{18}
$